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This is a method of solving the general quartic equation that my father showed me. The result is a very nice, compact and symmetric expression for the roots.
Problem Solve the quartic equation aX4+bX3+cX2+dX+e=0aX4+bX3+cX2+dX+e=0
for XX. Solution First divide through by aa and then substitute X=x−b4aX=x−4ab in order to eliminate the cubic term. This leaves us…
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