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Let $N(k,\ell)$ be the minimal $N$ such that for any $f:\{1,\ldots,N\}\to\{-1,1\}$ there must exist a $k$-term arithmetic progression $P$ such that\[ \left\lvert \sum_{n\in P}f(n)\right\rvert\geq \ell.\]Find good upper bounds for $N(k,\ell)$. Is it true that for any $c>0$ there exists some $C>1$ such that\[N(k,ck)\leq C^k?\]What about\[N(k,2)\leq C^k\]or\[N(k,\sqrt{k})\leq C^k?\]
When $\ell=k$ this is the van der Waerden number $W(k)$ (see [138]). Spencer [Sp73] has proved that if $k=2^tm$ with $m$ odd then\[N(k,1)=2^t(k-1)+1.\]Erdős and Graham write that 'no decent bound' is known even for $N(k,2)$.

Erdős [Er63d] proved that, for every $c>0$,\[N(k,ck)> (1+\alpha_c)^k\]where $\alpha_c\to 0$ as $c\to 0$ and $\alpha_c\to \sqrt{2}-1$ as $c\to 1$.

Hunter in the comment section observes that the local lemma implies an improved bound of\[N(k,ck) \gg \frac{2^k}{k^{O(1)}\sum_{i>\frac{1+c}{2}k}\binom{k}{i}},\]so that in particular as $c\to 1$ we have, for all large $k$, $N(k,ck)\geq (2-o(1))^k$ (where the $o(1)$ term $\to 0$ as $c\to 1$).
Additional thanks to: Zach Hunter
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This page was last edited 04 April 2026. (View history) (View the LaTeX source)

When referring to this problem, please use the original sources of Erdős. If you wish to acknowledge this website, the recommended citation format is:

T. F. Bloom, Erdős Problem #176, https://www.erdosproblems.com/176, accessed 2026-09-02

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