Control which (draws of) parameters should be saved in a brms
model. The output of this function is meant for usage in the
save_pars argument of brm.
Arguments
- group
A flag to indicate if group-level coefficients for each level of the grouping factors should be saved (default is
TRUE). Set toFALSEto save memory. Alternatively,groupmay also be a character vector naming the grouping factors for which to save draws of coefficients.- latent
A flag to indicate if draws of latent variables obtained by using
meandmiterms should be saved (default isFALSE). Saving these draws allows to better use methods such asposterior_predictwith the latent variables but leads to very large R objects even for models of moderate size and complexity. Alternatively,latentmay also be a character vector naming the latent variables for which to save draws.- all
A flag to indicate if draws of all variables defined in Stan's
parametersblock should be saved (default isFALSE). Saving these draws is required in order to apply the certain methods such asbridge_samplerandbayes_factor.- manual
A character vector naming Stan variable names which should be saved. These names should match the variable names inside the Stan code before renaming. This feature is meant for power users only and will rarely be useful outside of very special cases.
Examples
# \dontrun{
# don't store group-level coefficients
fit <- brm(count ~ zAge + zBase * Trt + (1|patient),
data = epilepsy, family = poisson(),
save_pars = save_pars(group = FALSE))
#> Compiling Stan program...
#> Start sampling
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 1).
#> Chain 1:
#> Chain 1: Gradient evaluation took 5.2e-05 seconds
#> Chain 1: 1000 transitions using 10 leapfrog steps per transition would take 0.52 seconds.
#> Chain 1: Adjust your expectations accordingly!
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#> Chain 1:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 2).
#> Chain 2:
#> Chain 2: Gradient evaluation took 2.6e-05 seconds
#> Chain 2: 1000 transitions using 10 leapfrog steps per transition would take 0.26 seconds.
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#> Chain 2:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 3).
#> Chain 3:
#> Chain 3: Gradient evaluation took 2.9e-05 seconds
#> Chain 3: 1000 transitions using 10 leapfrog steps per transition would take 0.29 seconds.
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#> Chain 3:
#>
#> SAMPLING FOR MODEL 'anon_model' NOW (CHAIN 4).
#> Chain 4:
#> Chain 4: Gradient evaluation took 2.5e-05 seconds
#> Chain 4: 1000 transitions using 10 leapfrog steps per transition would take 0.25 seconds.
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#> Chain 4:
variables(fit)
#> [1] "b_Intercept" "b_zAge" "b_zBase"
#> [4] "b_Trt1" "b_zBase:Trt1" "sd_patient__Intercept"
#> [7] "Intercept" "lprior" "lp__"
# }