Eigen
Eigenspace
Eigenvector
Eigenvalue
definition
let MM^n,n A /\ NN n /\ RR ll /\ RR^n x /\ x + O
if :Ax = llx, then x is an eigen›vector of A and ll is its corresponding eigen›value
theorems
let MM^n,n A /\ NN n
theorem there are infinitely many eigen›vectors for each eigen›value
theorem all eigen›vectors together with the zero vector form a vector space
theorem the characteristic polynomial "det" (A..llI) is a polynomial of degree n, meaning it has at most n distinct function › roots by the fundamental theorem of algebra
theorem A has at most n distinct eigen›values
theorem each eigen›value of A gives an eigen›space of vector space› dimension greater than 0
theorem eigen›vectors of A corresponding to distinct eigen›values are linearly independent ‹vectors
procedures
procedure finding eigen›values
:Ax = llx
O = :Ax..llx = :Ax..:(llI)x = :(A..llI)x = Othe equation above is a homogeneous linear system where
A..llIis the coefficient matrixrecall that a homogeneous linear system can have either a unique solution (with
x = O, which is not a valid eigen›vector as per the definition) or an infinite number of solutions (which we can achieve by picking the right values forll). for a homogeneous linear system to have an infinite number of solutions, the determinant of its coefficient matrix must be equal to0(see matrix › theorems)
"det" (A..llI) = 0(this polynomial is known as the characteristic polynomial ofA)solving...
using
A = []1 & 2 && 2 & 1[]as an example
A..llI = []1 & 2 && 2 & 1[] .. ll[]1 & 0 && 0 & 1[] = []1 ..ll & 2 && 2 & 1 ..ll[]
"det" (A..llI) = 0 = [1 .. ll]2 .. 4 = 1 .. ll : 2 | 1 .. ll .. 2 = 3 .. ll | ..1 .. ll = 0
ll = {3 \/ ..1}are the eigen›values ofA
procedure finding eigen›vectors
as
:(A..llI)x = O, we get the following (see matrix › null space):
E_ll = NN (A..llI), where
E_llis the eigen›space ofAcorresponding to the eigen›valuell(this vector space is called the λ-eigen›space ofA)the eigen›vectors of
Aassociated with the eigen›valuellare all the nonzero vectors inE_ll. therefore, instead of finding the eigen›vectors corresponding to the known eigen›value, we will find a basis for the eigen›spacefor
ll = 3:
:(A..3I)x = O
:(A..3I)x = :([]1 & 2 && 2 & 1[] .. []3 & 0 && 0 & 3[])x = :[]..2 & 2 && 2 & ..2[]x = 0therefore, we can solve the following linear system using row reduction
[]..2 & 2 & || & 0 && 2 & ..2 & || & 0[]and we get:
x = c(1, 1) > RR c
{{ (1, 1) }}is then a basis for the eigen›spaceE_3ofAnote the general solution of the homogeneous linear system will always be a basis as the resulting vectors will always be linearly independent ‹vectors, see matrix › null space for more information
for
ll = ..1, we get the basis{{ (1, ..1) }}for the eigen›spaceE_..1ofA
application
#todo mm
raising a matrix to a large power efficiently
let MM^n,n A /\ NN n be a diagonalizable ‹matrix
- construct a matrix
P = []|| & || & || && x_0 & x_1 & x_2 && || & || & ||[] = []x_0^0 & x_1^0 & x_2^0 && x_0^1 & x_1^1 & x_2^1 && x_0^2 & x_1^2 & x_2^2[]whose columns are thenlinearly independent ‹vector eigen›vectorsxofA - construct a matrix
D = []ll_0 & 0 & 0 && 0 & ll_1 & 0 && 0 & 0 & ll_2[]whose matrix › diagonal entries are the eigen›values ofAand all other entries equal to0, in the same order as the columns ofP
then, AP = PD. as the columns of P are linearly independent ‹vectors, we know P is an invertible matrix. therefore, A = PDP^- and P^- AP = D
proof the
nth column ofAPisAP^*,n = Ax_n. sincex_nis an eigen›vector ofA, we use its corresponding eigen›value to getAP^*,n = Ax_n = ll_n x_nby definition, see eigen. thenth column ofPDisPD^*,n. when multiplying out, we getPD^*,n = x_n D^n,n = x_n ll_n. asAP^*,n = PD^*,n -| NN n, we concludeAP = PD
now, compute [A]p /\ NN p with p being a very large integer
with A = PDP^-, we get [A]p = [PDP^-]p = P | [D]p | P^-
as D is a diagonal ‹matrix, we get [D]p = [] [ll_0]p & 0 & 0 && 0 & [ll_1]p & 0 && 0 & 0 & [ll_2]p []
computing [A]p = P[][ll_0]p & 0 & 0 && 0 & [ll_1]p & 0 && 0 & 0 & [ll_2]p[]P^- is now way less computationally expensive than computing [A]p directly
application
eigen›vectors and eigen›value can be useful in markov chains --- https://www.youtube.com/watch?v=JGQe4kiPnrU
Multiplicity
see multiplicity
definition the algebraic multiplicity of a function › root ll of the characteristic polynomial of A is its multiplicity
definition the geometric multiplicity of a function › root ll of the characteristic polynomial of A is the vector space› dimension of the eigen›space E_ll of A corresponding to the eigen›value ll
theorem let ll be an eigen›value of A. then, 1 -| "geometric multiplicity of" ll -| "algebraic multiplicity of" ll
example the characteristic polynomial of
[]2 & 4 & ..3 && 0 & 3 & 5 && 0 & 0 & 3[]is2 .. ll | [3 .. ll]2. its eigen›values arell = 2andll = 3. the algebraic eigen › multiplicity ofll = 2is1and the algebraic eigen › multiplicity ofll = 3is2.
applications
eigen › multiplicity can be used to determine whether a matrix is a diagonalizable ‹matrix