By Bernd Klein. Last modified: 03 Feb 2025.
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Definitions
A linear combination in mathematics is an expression constructed from a set of terms by multiplying each term by a constant and adding the results.
Example of a linear combination:
a · x + b · y is a linear combination of x and y with a and b constants.
Generally;
p = λ1 · x1 + λ2 · x2 … λn · xn
p is the scalar product of the values x1, x2 … xn and
λ1, λ2 … λn are called scalars.
In most applications x1, x2 … xn are vectors and the lambdas are integers or real numbers. (For those, who prefer it more formally:
x1, x2 … xn ∈ V and V is a vector space, and
λ1, λ2 … λn ∈ K with K being a field)
Linear Combinations in Python
The vector y = (3.21, 1.77, 3.65) can be easily written as a linear combination of the unit vectors (0,0,1), (0,1,0) and (1,0,0):
(3.21, 1.77, 3.65) = 3.21 · (1,0,0) + 1.77 (0,1,0) + 3.65 · (0,0,1)
We can do the calculation with Python, using the module numpy:
import numpy as np x = np.array([[0, 0, 1], [0, 1, 0], [1, 0, 0]]) y = ([3.65, 1.55, 3.42]) scalars = np.linalg.solve(x, y) scalars
OUTPUT:
array([3.42, 1.55, 3.65])
The previous example was very easy, because we could work out the result in our head. What about writing our vector y = (3.21, 1.77, 3.65) as a linear combination of the vectors (0,1,1), (1,1,0) and (1,0,1)? It looks like this in Python:
import numpy as np x = np.array([[0, 1, 1], [1, 1, 0], [1, 0, 1]]) y = ([3.65, 1.55, 3.42]) scalars = np.linalg.solve(x, y) scalars
OUTPUT:
array([0.66, 0.89, 2.76])
Another Example
Any integer between -40 and 40 can be written as a linear combination of 1, 3, 9, 27 with scalars being elements of the set {-1, 0, 1}.
For example:
7 = 1 · 1 + (-1) · 3 + 1 · 9 + 0 · 27
We can calculate these scalars with Python. First we need a generator generating all the possible scalar combinations. If you have problems in understanding the concept of a generator, we recommend the chapter "Iterators and Generators" of our tutorial.
def factors_set(): for i in [-1, 0, 1]: for j in [-1,0,1]: for k in [-1,0,1]: for l in [-1,0,1]: yield (i, j, k, l)
We will use the memoize() technique (see chapter "Memoization and Decorators" of our tutorial) to memorize previous results:
def memoize(f): results = {} def helper(n): if n not in results: results[n] = f(n) return results[n] return helper
Finally, in our function linear_combination() we check every scalar tuple, if it can create the value n:
@memoize def linear_combination(n): """ returns the tuple (i,j,k,l) satisfying n = i*1 + j*3 + k*9 + l*27 """ weighs = (1,3,9,27) for factors in factors_set(): sum = 0 for i in range(len(factors)): sum += factors[i] * weighs[i] if sum == n: return factors
Putting it all together results in the following script:
def factors_set(): for i in [-1, 0, 1]: for j in [-1, 0, 1]: for k in [-1, 0, 1]: for l in [-1, 0, 1]: yield (i, j, k, l) def memoize(f): results = {} def helper(n): if n not in results: results[n] = f(n) return results[n] return helper @memoize def linear_combination(n): """ returns the tuple (i,j,k,l) satisfying n = i*1 + j*3 + k*9 + l*27 """ weighs = (1, 3, 9, 27) for factors in factors_set(): sum = 0 for i in range(len(factors)): sum += factors[i] * weighs[i] if sum == n: return factors # calculate the linear combinations of the first 10 positive integers: for i in range(1,11): print(linear_combination(i))
OUTPUT:
(1, 0, 0, 0) (-1, 1, 0, 0) (0, 1, 0, 0) (1, 1, 0, 0) (-1, -1, 1, 0) (0, -1, 1, 0) (1, -1, 1, 0) (-1, 0, 1, 0) (0, 0, 1, 0) (1, 0, 1, 0)