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@@ -111,19 +111,32 @@ To appreciate how statisticians connect probabilities to data, the key is to und

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**Scalar example**

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Let $X$ be a scalar random variable that takes on the $I$ possible values

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$0, 1, 2, \ldots, I-1$ with probabilities

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Consider the following discrete distribution

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$$

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{\rm Prob}(X = i) = f_i, \quad

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$$

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where

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$$

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f_i \geqslant 0, \quad \sum_i f_i = 1 .

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$$

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We sometimes write

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$$

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X \sim \{{f_i}\}_{i=0}^{I-1},\quad f_i \geqslant 0, \quad \sum_i f_i = 1

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X \sim \{{f_i}\}_{i=0}^{I-1}

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$$

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Draw a sample $x_0, x_1, \dots , x_{N-1}$, $N$ draws of $X$ from $\{f_i\}^I_{i=1}$.

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as a short-hand way of saying that the random variable $X$ is described by the probability distribution $ \{{f_i}\}_{i=0}^{I-1}$.

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Consider drawing a sample $x_0, x_1, \dots , x_{N-1}$ of $N$ independent and identically distributoed draws of $X$.

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What do the "identical" and "independent" mean in IID or iid ("identically and independently distributed)?

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- "identical" means that each draw is from the same distribution.

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- "independent" means that the joint distribution equal tthe product of marginal distributions, i.e.,

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- "independent" means that joint distribution equal products of marginal distributions, i.e.,

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$$

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\begin{aligned}

@@ -132,11 +145,12 @@ $$

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\end{aligned}

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$$

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Consider the **empirical distribution**:

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We define an e **empirical distribution** as follows.

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For each $i = 0,\dots,I-1$, let

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$$

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\begin{aligned}

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i & = 0,\dots,I-1,\\

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N_i & = \text{number of times} \ X = i,\\

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N & = \sum^{I-1}_{i=0} N_i \quad \text{total number of draws},\\

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\tilde {f_i} & = \frac{N_i}{N} \sim \ \text{frequency of draws for which}\ X=i

@@ -425,7 +439,7 @@ Conditional distributions are

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$$

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\begin{aligned}

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\textrm{Prob}\{X=i|Y=j\} & =\frac{f_ig_j}{\sum_{i}f_ig_j}=\frac{f_ig_j}{g_i}=f_i \\

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\textrm{Prob}\{X=i|Y=j\} & =\frac{f_ig_j}{\sum_{i}f_ig_j}=\frac{f_ig_j}{g_j}=f_i \\

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\textrm{Prob}\{Y=j|X=i\} & =\frac{f_ig_j}{\sum_{j}f_ig_j}=\frac{f_ig_j}{f_i}=g_j

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\end{aligned}

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$$

@@ -609,7 +623,7 @@ $$

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\begin{aligned}

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\tilde{U} & =F(X)=1-\lambda^{x+1}\\

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1-\tilde{U} & =\lambda^{x+1}\\

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log(1-\tilde{U})& =(x+1)\log\lambda\\

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\log(1-\tilde{U})& =(x+1)\log\lambda\\

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\frac{\log(1-\tilde{U})}{\log\lambda}& =x+1\\

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\frac{\log(1-\tilde{U})}{\log\lambda}-1 &=x

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\end{aligned}

@@ -1561,7 +1575,7 @@ Now we'll try to go in a reverse direction.

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We'll find that from two marginal distributions, can we usually construct more than one joint distribution that verifies these marginals.

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Each of these joint distributions is called a **coupling** of the two martingal distributions.

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Each of these joint distributions is called a **coupling** of the two marginal distributions.

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Let's start with marginal distributions

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