ol reverse attribute polyfill

	//a polyfill for the ordered-list reversed attribute
	// http://www.whatwg.org/specs/web-apps/current-work/multipage/grouping-content.html#the-ol-element
	// http://www.whatwg.org/specs/web-apps/current-work/multipage/grouping-content.html#dom-li-value

	//uses these awesomeness:
	// Array.prototype.forEach
	// Element.prototype.children
	//if you want support for older browsers coughIE8-cough, then use the other
	// file provided
	(function () {
	"use strict";

	if ( 'reversed' in document.createElement('ol') ) {
	return;
	}

	[].forEach.call( document.getElementsByTagName('ol'), function ( list ) {
	if ( list.getAttribute( 'reversed' ) !== null ) {
	reverseList( list );
	}
	});

	function reverseList ( list ) {
	var children = list.children, count = list.getAttribute('start');

	//check to see if a start attribute is provided
	if ( count !== null ) {
	count = Number( count );

	if ( isNaN(count) ) {
	count = null;
	}
	}

	//no, this isn't duplication - start will be set to null
	// in the previous if statement if an invalid start attribute
	// is provided
	if ( count === null ) {
	count = children.length;
	}

	[].forEach.call( children, function ( child ) {
	child.value = count--;
	});
	}
	}());

	//use this if you want support for browsers which don't have ES5 goodies
	(function () {
	if ( 'reversed' in document.createElement('ol') ) {
	return;
	}

	var lists = document.getElementsByTagName( 'ol' );

	for ( var i = 0, len = lists.length; i < len; i++ ) {
	if ( lists[i].getAttribute( 'reversed' ) !== null ) {
	reverseList( lists[i] );
	}
	}

	function reverseList ( list ) {
	var children = [], childNodes = list.childNodes,
	count = list.getAttribute('start'), i, len;

	for ( i = 0, len = childNodes.length; i < len; i++ ) {
	//Node.ELEMENT_NODE === 1
	if ( childNodes[i].nodeType === 1 ) {
	children.push( childNodes[i] );
	}
	}

	//check to see if a start attribute is provided
	if ( count !== null ) {
	count = Number( count );

	if ( isNaN(count) ) {
	count = null;
	}
	}

	//no, this isn't duplication - start will be set to null
	// in the previous if statement if an invalid start attribute
	// is provided
	if ( count === null ) {
	count = children.length;
	}

	for ( i = 0, len = children.length; i < len; i++ ) {
	children[ i ].value = count--;
	}
	}
	}());